/*
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Anser:25164150
Time:11.779µs
*/
package main

import (
	"fmt"
	"time"
)

func main() {
	tstart := time.Now()
	sumOfSquares, squareOfSum := 0, 0
	for i := 1; i <= 100; i++ {
		sumOfSquares += i * i
		squareOfSum += i
	}
	squareOfSum *= squareOfSum
	fmt.Println(squareOfSum - sumOfSquares)
	tend := time.Now()
	fmt.Println(tend.Sub(tstart))
}
